Question

1)simplify 1/2(a-2b)+3/2(b-2a)
2)how much is a³-3a²b+3ab²+b³ less than a³+3a²b+3ab²+b³?​

Answer 1

Answer:

1) 7a/2 + 5b/2

2) by 6a²b

Step-by-step explanation:

1) 1/2(a- 2b) + 3/2(b - 2a)

= a/2 + b + 3b/2 - 3a

= a/2 - 3a + b + 3b/2

= a+6a/2 + 2b+3b/2

= 7a/2 + 5b/2

2) a³ + 3a²b + 3ab² + b³ - (a³- 3a²b + 3ab² + b³)

= a³ + 3a²b + 3ab² + b³ - a³ + 3a²b - 3ab² - b³

= a³ - a³ + 3a²b + 3a²b + 3ab² - 3ab² + b² - b²

= 6a²b