Question

1) Simplify: 4y (y2

– y + 1) and find its value for (i) y = –1 and (ii) y = 2

Answer 1

Answer:

I hope this helps

Plz mark as brainlest

Answer 2

Answer:

i) -16 and ii) 24

Step-by-step explanation:

4y(y^2-y+1) = 4y^3-4y^2+4y

when y = -1 : 4(-1)^3-4(-1)^2+4(-1)

4(-1)-4(1)+4(-1)

-4-4-4

-16

when y = 2 : 4(2)^3-4(2)^2+4(2)

4(8)-4(4)+4(2)

32-16+8

24