Question

1.Simplify:(a+b–c)+(a–b+c)+(-a+b+c)

2.Thrice a number when increased by 5 gives 44. Find the number.​

Answer 1

Question 1.

Simplify:(a+b–c)+(a–b+c)+(-a+b+c)

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$\huge \tt \: ☃ \: Solution$

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⇒(a+b–c)+(a–b+c)+(-a+b+c)

• First solve the brackets.

⇒a + b - c + a - b + c - a + b + c

• Collect like terms

⇒a + a - a + b - b + b - c + c + c

⇒a + b + c

Hence, simplify.

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Question 2.

Thrice a number when increased by 5 gives 44. Find the number.

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Step by step explanation:-

To find:-

• The number

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$\huge \tt \: ☃ \: Solution$

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Let the number be x.

So, According to question:-

⇒3x + 5 = 44

⇒3x = 44 - 5

⇒3x = 39

⇒x = 39/3

⇒x = 13

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Verification:-

⇒3x + 5 = 44

• Put x = 13

⇒3× ( 13) + 5 = 44

⇒39+ 5 = 44

⇒44 = 44

Hence,verified

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Thus , the number is 13.