Question

1. Simplify the Boolean expression (A+B'+AB)(A+B')(A'B). ​

Answer 1

Explanation:

It’s already simplified enough (DNF). What you have written is the expansion of xor gate.

A’B + AB’ = A⊕B

Heres a way to get CNF

A’B + AB'

(A’ + AB’)(B + AB’)

(A’ + A)(A’+B’)(B+B’)(B+A)

(A’+B’)(A+B)