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sin 0 + sin2 0 = 1,
ow that :
cos2 0 + cos4 @ = 1. in step by t
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→ sinθ + sin²θ = 1
To prove :-
→ cos²θ +cos⁴θ = 1
Proof:-
→ sinθ + sin²θ = 1
→ sinθ = 1 - sin²θ
→ sinθ = cos²θ [ 1- sin²θ= cos²θ]
Squaring on both side
→ sin²θ = cos⁴θ
→ 1 - cos²θ = cos⁴θ [ sin²θ= 1- cos²θ]
→ 1 = cos⁴θ + cos²θ
→ cos⁴θ + cos²θ = 1
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