Question

(1+sin∅)(1-sin∅)/(1+cos∅)(1-cis∅)​

Answer 1

Answer:

CORRECT QUESTION :

= $\dfrac {(1 + sin \theta)(1 - sin \theta)}{(1 + cos \theta)(1 - cos \theta)}$

SOLUTION :

= $\dfrac {(1 + sin \theta)(1 - sin \theta)}{(1 + cos \theta)(1 - cos \theta)}$

= $\dfrac {1 - sin{(\theta)}^{2}}{(1 + cos \theta)} \times {(1 - cos \theta)}$

= $\dfrac {1 - sin {(\theta)}^{2}}{1 - cos {(\theta)}^{2}}$

= $\dfrac {cos {(\theta)}^{2}}{1 - cos {(\theta)}^{2}}$

= $\dfrac {cos {(\theta)}^{2}}{sin {(\theta)}^{2}}$

= $\dfrac {cos {(\theta)}^{2}}{sin {(\theta)}}</p><p>$

= $cot {(\theta)}^{2}$

We need to know,

→ $\dfrac {sin (\theta)}{cos (\theta)} = tan \theta$

→ $\drac {cos (\theta)}{sin (\theta)} = </p><p>cot \theta$

→ $(a-b)(a+b) = {a}^{2} - {b}^{2}$