Math, asked by ammusree118, 2 months ago

(1+sin)(1-sin)=1÷sec^2​

Answers

Answered by kushisachdeva76
1

Answer:

LHS = RHS

Step-by-step explanation:

( 1 + sin )( 1 - sin ) = 1 / sec^2

LHS = ( 1 + sin )( 1 - sin )

= 1 - sin^2

using identity (a+ b)(a - b) = ( a^2 - b^2 )

= cos^2

As 1 - sin^2 = cos^2

= 1 / sec^2

As cos^2 = 1 / sec ^2

RHS = 1 / sec^2

LHS = RHS

Hence , Proved .

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