Math, asked by pakhiqueen1717, 7 months ago

√1+sin÷1-sin+√1-sin÷1+sin​

Answers

Answered by DEBOBROTABHATTACHARY
1

(√1+sin@/1-sin@) + (√1-sin@/1+sin@)

= {(√1+sin@)^2+ (√1-sin@)^2} / (1-sin^2@)

= 2(1+sin^2@) / cos^2@

= 2(-cos^2@) / cos^2@

= -2

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