Question

√1+sin/1-sin=sec+tan​

Answer 1

Answer:

Given,

√1+ sin/ 1- sin = sec + tan

L.H.S,

√1+ sin/ 1- sin

Now,

Rationalise √1+ sin/1- sin

= √1+ sin/1-sin × 1+sin/ 1+sin

= √1^2+ sin^2/ 1-sin.1+sin

= √1+ sin^2/ 1^2 - sin^2

[Since, denominator is (a+b)(a-b) = a^2 - b^2 formula]

= √1+ sin^2/ 1- sin^2

= √1+ sin^2/ cos^2

= √(1+ sin/ cos)^2

= 1+ sin/ cos [Since, cancelation for square and root]

Now,

= 1/cos + sin/cos

= sec + tan

=R.H.S

Explanation:

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