1 -sin^2A =tan^2A to show sin^2A=1+cos^2A/cos^2A
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Answer is:-
1-sin^2A=tan^2A
cos^2A=tan^2A
1+cos^2A/cos^2A
=1+tan^2A/tan^2A
=sec^2A/tan^2A
=sinA
1-sin^2A=tan^2A
cos^2A=tan^2A
1+cos^2A/cos^2A
=1+tan^2A/tan^2A
=sec^2A/tan^2A
=sinA
akhand45:
isse 1/sin^2A aaega
Closest I could go
you can do this question or not
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