Question

((1+sin^2Q)÷cos^Q) = 1+2tan^2Q​

Answer 1

Answer:

answer for the given problem is given

Answer 2

$\frac{1+sin^2Q}{cos^2Q} = 1+2tan^2Q$

Taking L.H.S

$=\frac{(1+sin^2Q)}{cos^2Q}$

$=\frac{1}{cos^2Q}+\frac{sin^2Q}{cos^2Q}$

$=sec^2Q+tan^2Q$

Taking R.H.S

$1+2tan^2Q$

$1+tan^2Q+tan^2Q$

$sec^2Q+tan^2Q$

We can see that

L.H.S=R.H.S

Hence proved

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Identity used

$i):\frac{1}{cosQ}=secQ$

$ii):\frac{sinQ}{cosQ}=tanQ$

$iii):1+tan^2Q=sec^2Q$

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