Question

1+ sin 2x + cos2x / cOS X + sin x
= 2 cos x​

Answer 1

Answer:

$1 + \sin(2x) + \cos(2x) \div \sin(x) + \cos(x)$

Step-by-step explanation:

1+2sinxcosx+cos²x–sin²x/cosx+sinx

=> 1-sin²x+cos²x+2sinxcosx/cosx+sinx

=>2cos²x+2sinxcosx/cosx+sinx

=>2cosx(cosx+sinx)/cosx+sinx

=>2cosx. ....(proved)