Question

1. (Sin 30°+cos 60°)-(sin 60° + cos
30°) is equal to:​

Answer 1

Explanation:

We know that,

$\sin 60 \degree = \frac{ \sqrt{3} }{2}$

$\cos60 \degree = \frac{1}{ 2}$

$\sin30 \degree = \frac{1}{2}$

$\cos30 \degree = \frac{ \sqrt{3} }{2}$

$(Sin 30°+cos 60°)-(sin 60° + cos</p><p>30°)$

$(\frac{1}{2} + \frac{1}{2} ) - ( \frac{ \sqrt{3} }{2} + \frac{ \sqrt{3} }{2} )$

$\frac{2}{2} - \frac{ 2\sqrt{3} }{2}$

$\frac{2 - 2 \sqrt{3} }{2}$

$\frac{ \not2(1 - \sqrt{3} )}{ \not2}$

$\boxed{1 - \sqrt{3} }$