Question

1. (Sin 30°+cos 60°)-(sin 60° + cos
30°) is equal to:​

Answer 1

$\large{\text{\red{A}}}{\text{\orange{N}}{\text{\green{S}}{\text{\purple{W}}{\text{\blue{E}}{\text{\pink{R}}{\text{\gray{:-}}}}}}}}$

$\sf{\blue{\frac{1}{2}}}$

$\large{\red{{\fbox{Given:-}}}}$

(Sin 30°+cos 60°)-(sin 60° + cos 30°)

$\large{\red{{\fbox{Solution:-}}}}$

$\bf{ = > ( \frac{ \sqrt{3}}{2})( \frac{ \sqrt{3} }{2}) - ( \frac{1}{2})( \frac{1}{2}) }$

${\huge[}{\bf{∵cos30 {}^{0} = sin 60{}^{0} = \frac{ \sqrt{3}}{7},sin30 {}^{0} = cos60 {}^{0}{\huge}] }}$

$\bf{ = > {\large(}\frac{ \sqrt{3}}{7}{\large)} {}^{2} - {\large(}\frac{{1}}{2}{\large)} {}^{2}}$

$\bf{ = > \frac{3}{4} - \frac{1}{4} }$

$\bf{ = > \frac{2}{4} }$

$\bf{ = > \frac{1}{2} }$