1-sin 60°/cos 60=1-tan30/1+tan 30
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que. 1 - sin 60°/ cos60°. = 1-tan 30/1 + tan 30°
solution =
= √3/2 /. 1/2
=. √3 l.h.s.
= 1-1/√3/1 + 1/√3
= 1-1/√3 + 1/√3
=. 0/√3 + 1/√3
=. 0 + 1/√3
=. √3 r.h.s.
that's solved
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