Question

1 + sin a / 1 + cot a is equal to 1 minus 10 a divided by 1 minus cot a whole square minus 10 square A​

Answer 1

⇔ HEY

⇔ See the attchment

[tanA/(1-cotA)]+[cotA/(1-tanA)]

=[tanA/(1–1/tanA)]+[cotA/(1-tanA)]

=[tan²Α/(tanA-1)]- [cotA/(tanA-1)]

= (tan²Α-cotA)/(tanA-1)

= [tan²A-(1/tanA)]/(tanA-1)

=( tan³Α-1)/(tanA-1)tanA

= (tanA-1)(tan²Α+1+tanA)/(tanA-1)tanA

= (tan²Α+tanA+1)/tanA

=1+tanA+cotA

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