Question

(1-sin A)/(1+ sin A)=(sec A-tan A)²
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Answer 1

Answer:

(1-sinA) /(1+sinA) =(secA-tanA) ^2

Hence proved

Step-by-step explanation:

=(1-sinA)/(1+sinA) ×(1-sinA)/(1-sinA)

=(1-sinA) ^2/(1) ^2-(sinA) ^2

=(secA-tanA) ^2

Hence proved