√1-sin A / 1+sin A = sec A - tan A
Solve this.
kvnmurty:
u should use parentheses { (1-Sin A)/(1+Sin A) } like this.
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⇒√1-sin A/1+sin A*√1-sin A/1-sin A
⇒√[1-sin A]²/1-sin²A
⇒√[1-sin²A]/cos²A
⇒1-sin A/cos A
⇒1/cos A-sin A/cos A
⇒sec A-tan A
hence proved.
⇒√[1-sin A]²/1-sin²A
⇒√[1-sin²A]/cos²A
⇒1-sin A/cos A
⇒1/cos A-sin A/cos A
⇒sec A-tan A
hence proved.
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