Question

√1+sin A/√1-sin A=sec A+tanA​

Answer 1

Step-by-step explanation:

√(1+sinA/1-sinA)*(1+sinA/1+sinA)

√(1+sinA)²/1-sin²A

√{1+sinA/cosA)²

1+sinA/cosA

secA + tanA

Answer 2

Answer:

Hence, Proved

I hope the answer helps you. ^_^