Math, asked by reenashaw206, 11 months ago

1 + sin A / cos A + cos A / 1 + sin A = 2 sec A

please solve this problem

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Answers

Answered by radha2216

1

Step-by-step explanation:

LHS

1+sinA + cosA

cosA. 1+ sinA

**= ( 1+SinA)² + *cos²***A

=. cosA (1+ sinA)

=. 1 + sin²+2sinA+ cos²A

cosA ( 1+ sinA)

=. 2+2 sinA

cosA (1+sinA)

=. 2(1+sinA) / cosA(1+sinA)

=. 2/cosA

=. 2secA

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