Question

(1 - sin  + cos )2 = 2(1 + cos )(1  sin ).

Answer 1

Answer:

Step-by-step explanation: LHS=(1- sinA+cosA)^2. =[(1-sinA)+cosA]^2. =(1-sinA)^2+cos^ A+2(1-sinA)cosA. =1+sin^2A-2sinA+cos^2A+2(1-sinA )

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Answer 2

Answer:

       =1+sin^2A-2sinA+cos^2A+2(1-sinA )

Step-by-step explanation:

LHS=(1- sinA+cosA)^2.

       =[(1-sinA)+cosA]^2.

       =(1-sinA)^2+cos^ A+2(1-sinA)cosA.

       =1+sin^2A-2sinA+cos^2A+2(1-sinA )