Question

1 + sin
cos
+
cos
1 + sin
=
2 sec
​

Answer 1

Answer:

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Answer 2

$\ {\bold\purple{\dfrac{Cos \ A}{1 + Sin \ A} + \dfrac{1 + Sin \ A}{Cos \ A} = 2 \ sec \ A}}$

$\: \: \: \: \: \: \: \: \: \: \: \:$

$\begin{gathered}\implies\sf \dfrac{Cos \ A}{ 1 + Sin \ A} + \dfrac{1 + Sin \ A}{Cos \ A} \\\\\\:\implies\sf\dfrac{ Cos^2 A + \Bigg[1 + Sin \ A \Bigg]^2}{\Bigg[1 + Sin \ A \Bigg] Cos \ A} \\\\\\:\implies\sf \dfrac{ Cos^2 \ A + 1 \ Sin^2 \ A + 2 \ Sin \ A}{\Big[1 + Sin \ A \Big] + Cos \ A}\\\\\\:\implies\sf \dfrac{ 2 + 2 \ Sin \ A}{Cos \ A \Big[ 1 + Sin \ A \Big]}\\\\\\:\implies\sf \dfrac{ 2}{Cos \ A} \\\\\\:\implies{\bold\purple{ 2 \ Sec \ A}}\end{gathered}$

$\qquad\qquad{\bold\pink{Hence \ Proved!!}}$