Question

1+sin theta/1+cos theta =(sec theta - tan theta)the whole square

Answer 1

The question given is wrong. There should be 1+sin theta instead of 1+cos theta.    

 

 

 (1-sin\theta )/(1+sin\theta )
=(1-sin\theta )/(1+sin\theta )*(1-sin\theta )/(1-sin\theta )
=((1-sin\theta )(1-sin\theta ))/((1+sin\theta )(1-sin\theta ))
=((1-sin\theta )^(2))/((1-sin^(2)\theta ))
=((1-sin\theta )^(2))/(cos^(2)\theta )
=((1-sin\theta )/(cos\theta ))^(2)
=((1)/(cos\theta )-(sin\theta )/(cos\theta ))^(2)
=(sec\theta -tan\theta )^(2)