Question

(1+sin theta)(1_sin theta)/(1+cos theta)(1_cos theta)​

Answer 1

( 1+ sin ) (1- sin) (1+cos) (1-cos)

= (1-sin^2) ( 1- cos^2)

= 1 -cos^2 - sin^2 + sin^2cos^2

= 1 - ( sin^2 + cos^2 ) + sin^2cos^2

= 1 - 1 +sin^2cos^2

= sin^cos^2