1 + sin theta/1- sin theta+
1- sin theta/1+ sin theta
= 2 (sec^2 theta + tan^2 theta )
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Answer:
Step-by-step explanation:
1 + Sinθ/1 - Sinθ + 1 - Sinθ/1 + Sinθ
//Take LCM
=> (1 + Sinθ)² + (1 - Sinθ)² / (1 + Sinθ)(1 -Sinθ)
=> 1 + Sin²θ+2Sinθ + 1 + Sin²θ - 2Sinθ / 1 - Sin²θ
=> 2(1 + Sin²θ) / Cos²θ
=> 2(1/Cos²θ + Sin²θ/Cos²θ)
=>2(Sec²θ + Tan²θ)
=> R.H.S
Hence proved.
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