Question

1+sin theta/1-sin theta - 1-sin theta/ 1+sin theta = 4+tan theta. sec theta.plzzzzz plzzzzzzzzz answer it. It's too urgent plzzzzzz

Answer 1

Step-by-step explanation:

1+sin¢/1-sin¢ - 1-sin¢/1+sin¢

={(1+sin¢)²-(1-sin¢)²}/1-sin²¢

=4sin¢/cos²¢

=4sin¢/cos¢×1/cos¢

=4tan¢×sec¢ prove.

Answer 2

Answer:

I'm writing theta as A due to typing limitation to minimise error

LHS= [(1+sinA)/(1-sinA)] - [(1-sinA)/(1+sinA)]

= [(1+sinA)^2-(1-sinA)^2]/[(1-sinA)(1+sinA)]

= (1+2sinA+sin^2A-1+2sinA-sin^2A)/(1-sin^2A)

= 4sinA/cos^2A

= 4tanAsecA

= RHS

The error in question could be due to typing error.