Question

(1-sin theta+cos theta)^2=2 (1+ cos theta)(1-sin theta)​

Answer 1

Answer:

LHS=(1−sinθ+cosθ)  

2

 

LHS=1+sin  

2

θ+cos  

2

θ−2sinθ+2cosθ−2sinθcosθ

LHS=2−2sinθ+2cosθ−2sinθcosθ

LHS=2(1−sinθ)+2cosθ(1−sinθ)

LHS=2(1−sinθ)(1+cosθ)=RHS

Step-by-step explanation:

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