Question

(1-sin theta +cos theta)²=2(1+cos theta)(1-sin theta)​

Answer 1

ANSWER

LHS=(1−sinθ+cosθ)2

LHS=1+sin2θ+cos2θ−2sinθ+2cosθ−2sinθcosθ

LHS=2−2sinθ+2cosθ−2sinθcosθ

LHS=2(1−sinθ)+2cosθ(1−sinθ)

LHS=2(1−sinθ)(1+cosθ)=RHS