Math, asked by priyakumarimas269, 9 months ago

(1-sin theta + cos theta) square=2(1+cos theta) (1-sintheta)​

Answers

Answered by ibrahimhaque15jun200
0

Answer:

answers/16-sin-cube-theta-8-cos-cube-theta-and- answer-is-3-3447247

Thumbnail image

16 sin cube theta+8 cos cube theta= and answer is 3. Related Answer. sinθ+ cosθ=√2 then sin16θ is (A) cos16θ210 (B) sec16θ28 (C) 12sec16θ (D) ...

Step-by-step explanation:

answers/16-sin-cube-theta-8-cos-cube-theta-and- answer-is-3-3447247

Thumbnail image

16 sin cube theta+8 cos cube theta= and answer is 3. Related Answer. sinθ+ cosθ=√2 then sin16θ is (A) cos16θ210 (B) sec16θ28 (C) 12sec16θ (D) ...

Answered by souvikghosh738
1

Step-by-step explanation:

let, theta = x

(1-sin x+cos x)²

=1²+(sin x+ cos x)²-2*(sin x+ cos x)*1

=1+sin²x+cos²x+2*sin x*cos x-2sin x-2cos x

=1+1+2*sin x*cos x-2sin x-2cos x

=2-2sin x+2*sin x*cos x-2cos x

=2(1-sin x)+2 cos x(1-sinx)

=(1-sin x)(2+2cos x)

=2(1+cos x)(1-sin x)

=2(1+cos theta)(1-sin theta)

[proved]

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