Question

1 - sin theta + cos theta whole square equals to 2 into 1 minus sin theta into 1 + cos theta ​

Answer 1

I cannot understand your question.Please use brackets to make the question accurate.

Answer 2

Answer:

Step-by-step explanation:

(1-sinA+cosA)^2=2(1-sinA)(1+cosA)

think 1-sinA as 1 unit and use the formula (a+b)^2=a^2+b^2+2.a.b

(1-sinA)^2 + cos^2A+ 2.(1-sinA).cosA

1+sin^2A- 2.sinA +cos^2A + 2 cosA - 2sinAcosA

1+sin^2A+cos^2A-2sinA+2cosA-2sinAcosA    since sin^2A+cos^2A=1

1+1-2sinA+2cosA-2sinAcosA

2-2sinA+2cosA-2sinAcosA taking 2 as common

2[1-sinA+cosA-sinAcosA] taking cosA as common

2[1-sinA+cosA[1-sinA]] taking 1-sinA as common

2[1-sinA][1+cosA]