Question

√1-sin0/1+sin0=sec0-tan0​

Answer 1

Answer:

this is the answer..

hope this would help

Answer 2

Answer:

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Step-by-step explanation:

√[(1+sina)/(1-sina)]

= √[(1+sina)(1+sina)/(1-sina)(1+sina)]

=√[(1+sina)²/(1-sin²a)]

=√[(1+sina)²/cos²a]

=(1+sina)/cosa

=1/cosa. +sina/cosa

=seca+tana

proved.✌✌✌✌✌✌✌✌✌