Math, asked by mikeroy, 1 year ago

1/sin10-√3/cos10=8cos20


MANIDEEP45: what is to find

Answers

Answered by MADHANSCTS
5
 \frac{1}{sin10}- \frac{ \sqrt{3} }{cos10}

 \frac{cos 10 - \sqrt{3}sin10 } {sin10.cos10}

 \frac{ \frac{2}{2} (cos 10 - \sqrt{3}sin10) } { \frac{2}{2} (sin10.cos10)}

 \frac{ 2(\frac{1}{2} cos 10 -  \frac{\sqrt{3}}{2} sin10) } { \frac{1}{2} (2sin10.cos10)}

 \frac{ 2(cos60.cos 10 - sin60. sin10) } { \frac{1}{2}.sin20}

 \frac{ 2(cos(60+10) } { \frac{1}{2}.sin20}

 \frac{ 4.cos70 } {sin20}

 \frac{ 4.sin20 } {sin20}

4
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