Question

1/sin10° - √3/cos10°

Answer 1

Answer:

1/sin10-√3/cos10

= (cos10 - √3sin10)/cos10sin10

multiplying 1/2 in denominator and numerator

= {(cos10/2) - (√3sin10/2)}/(cos10sin10/2)

= (cos60cos10 - sin60sin10)/(cos10sin10/2)

= cos(60 + 10)/(cos10sin10/2)

= cos70/(cos10sin10/2)

= 2cos70/cos10sin10

multiplying 2 on numerator and denominator

= 4cos70/2sin10cos10

=4cos70/sin20

=4cos70/cos70

= $4$ proved