Question

1.sin10ºsec80º=

0

1

-1



2.cos⁶θ+sin⁶θ+3sin²θcos²θ=

7

6

1

-1


3.Among the following a correct statement is

sin30º>sin60º

cos5º>cos45º

tan60º<tan30º

cos60º>cos30º



4.(secA+tanA)(1-sinA)=

secA

sinA

cosA

tanA



5.If x=secθ+tanθ, y=secθ-tanθ then

x+y=1

xy=1

x/y=1

x²+y²=1



6.If secx+tanx=2 then secx-tanx=

2

-2

(2)⁻¹

4



7. 9sec²A-9tan²A=

1

9

-9

0



8.sec16ºcosec74º-cot74ºtan16º=

0

1

1/2

-1


9.If 4sin²A-1=0 then cosA=

0

1

1/2

√3/2



10.If sinA=cosA then tanA=

0

1/2

-1

1


​

Answer 1

Answer:

sorry I can't understand your question

Answer 2

Answer:

1) sin 10° sec 80°

=> sin 10° sec ( 90 - 10)

=> sin 10° cosec 10°

=> sin 10° × 1/sin 10°

=> 1

3) cos 5° > cos 45°

because as the angle increase, value decreases for cos

example: cos 0° = 1, cos 60° = 1/2 , cos 90° = 0

10) if sin A = cos A then tan A = 1

sin A = cos A

sin A/cos A = 1

=> tan A = 1

9) if 4 sin²A = 1 then cos A = √3/2

sin²A = 1/4

sin A = √(1/4)

=> sin A = 1/2

=> sin A = sin 30°

=> A = 30°

=> cos A = cos 30° = √3/2

8) sec 16° cosec 74° - cot 74° tan16° = 1

sec 16° cosec (90° - 16°) - cot (90 - 16°) tan 16°

=> sec 16° sec 16° - tan 16° tan16°

=> sec²16° - tan²16°

=> 1 [ sec²x - tan²x = 1]

7) 9 sec²A - 9 tan² A = 9

=> 9 ( sec²A - tan²A )

=> 9 [ sec²A - tan²A = 1 ]