1/sin2α−1/sin2β=(cos2α−cos2β)/sin2α⋅sin2β
Answers
Answered by
0
Answer:
8nuvy unubu 8iuhb iiuu7 juubhb
Similar questions
Social Sciences,
5 months ago
Math,
5 months ago
Computer Science,
5 months ago
English,
10 months ago
English,
1 year ago
Geography,
1 year ago