(1-sin²∅)(1+tan²∅)=?????????
ATC:
what is there beside sin ^2 and tan^2-hey,is it Saturn?
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we know trigonometric identities
sin^2∆+cos^2∆=1
take ∆ as thita
and sec^2∆=1+tan^2∆
so using this identities equation becomes
(cos^2∆)(sec^2∆)
and we also know that
cos∆=1/sec∆
so answer is 1
sin^2∆+cos^2∆=1
take ∆ as thita
and sec^2∆=1+tan^2∆
so using this identities equation becomes
(cos^2∆)(sec^2∆)
and we also know that
cos∆=1/sec∆
so answer is 1
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