Question

1+sin2¤=3sin¤cos¤
P.T tan¤is either 1/2 or 1

Answer 1

HELLO DEAR,

let THETA=(alpha)
we know that:
$1 = { \sin}^{2} \alpha + { \cos }^{2} \alpha$
$\sin ^{2} ( \alpha ) + \cos ^{2} ( \alpha ) + \sin ^{2} ( \alpha ) = 3 \sin( \alpha ) \cos( \alpha )$
divede by {cos²(alpha)}

we get,

$1 + 2 \tan^{2} ( \alpha ) = 3 \tan( \alpha ) \\ = > 2 \tan ^{2} ( \alpha ) - 3 \tan( \alpha ) + 1 = 0 \\ = > (2 \tan( \alpha ) - 1)( \tan( \alpha ) - 1) = 0 \\ = > \tan( \alpha ) = \frac{1}{2 } \\ \tan( \alpha ) = 2$
I HOPE ITS HELP YOU DEAR,
THANKS