Question

1/sin20 + √3/cos20 = 4cot40

Answer 1

Answer:

solution;

LHS  

= ( √3 / sin 20° ) - ( 1 / cos 20° )  

= 2 [ (√3/2) / sin 20° ] - [ (1/2) / cos 20° ]  

= 2 [ ( sin 60° / sin 20° ) - ( cos 60° / cos 20° ) ]  

= 2 sin ( 60° - 20° ) / ( sin 20° cos 20° )  

= 2 sin ( 2 · 20° ) / ( sin 20° cos 20° )  

= 2 ( 2 sin 20° cos 20° ) / ( sin 20° cos 20° )  

= 4  

= RHS

Proved.

Step-by-step explanation:

Answer 2

Step-by-step explanation:

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