Question

√1-sin²100
sec 100°=

Answer 1

Given: The term √1-sin²100  sec 100°

To find: The value of the given term?

Solution:

• Now the term provided is trigonometric, which is:

                   √(1-sin²100°)  x sec 100°

• Now we know sin^2 x + cos^2 x = 1

• So applying it, we get:

                   √(1-sin²100°)  x sec 100° = √(cos²100°)  x sec 100°

                                                            = cos 100°  x sec 100°

• Now we know that cos x × sec x = 1

                   cos 100°  x sec 100° = 1

Answer:

            So the value of √1-sin²100  sec 100°  is 1.

Answer 2

Step-by-step explanation:

(√1-sin^2100°)sec100°

(√cos^2100°)×sec100°

cos100°×sec100°

=1

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