Question

(1-sin2A)/(1+sin2A)​

Answer 1

Answer:

(Sin A - Cos A)^2/(Sin A + Cos A)^2

Step-by-step explanation:

*Sin^2A + Cos^2A = 1 ...

*2.SinA.CosA = Sin 2A ... break the whole equation on this formula.

Answer 2

Answer:

$1 + sin2a = {cos}^{2} a + {sin}^{2} a + 2sina \: cosa = {(cosa \: + sina)}^{2} \\ 1 - \: sin2a = {cos}^{2} a + {sin}^{2} a - 2sina \: cosa = {(cosa \: - sina)}^{2} \\ \frac{1 - sin2a}{1 + sin2a} = \frac{{(cosa \: - sina)}^{2} }{{(cosa \: + sina)}^{2} } \\ = {( \frac{cosa \: - sina}{cosa \: + sina}) }^{2} \\ = {( \frac{1 - tana}{1 + tana}) }^{2} \\ = {tan}^{2} ( \frac{\pi}{4} - a)$