1-sin2A/1+sin2A=tan^2(π\4-A)
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proved.................
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Answered by
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remember 2 formulas.
1-sin2a =( cosa-sina)^2
1+sin2A=(cosA+sinA)^2
1+-tanA/1-+tanA=tan(¥/4+-A)
1-sin2a =( cosa-sina)^2
1+sin2A=(cosA+sinA)^2
1+-tanA/1-+tanA=tan(¥/4+-A)
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