Math, asked by kanha584, 1 year ago

1-sin2A/1+sin2A=tan^2(π\4-A)

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Answered by mistyque

8

proved.................

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Answered by captain56

8

remember 2 formulas.

1-sin2a =( cosa-sina)^2
1+sin2A=(cosA+sinA)^2
1+-tanA/1-+tanA=tan(¥/4+-A)

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