Question

1+sin²A=3 SinA.CosA Prove that tan²A=1 or 1/2​

Answer 1

Answer:

1 + sin²A = 3 sinA cos A  

cos²A + 2 sin²A = 3 sinA cosA (1= cos²A + sin² A)  

cotanA + 2 tanA = 3 ( all this * tan A)  

1 + 2 tan²A =3 tanA  

2 tan²A - 3 tanA +1 = 0  

2 (tanA -1)*(tanA-1/2) =0  

then tan A = 1 or tan A =1/2