Question

1-sin2a+cos2a/1+sin2a+cos2a=tan(π/4-a)

Answer 1

Hi______
im using

sin2a=2sinacosa

cos2a=2cos^2a-1

tan(a-b)=tana-tanb/1+tanatanb

here i solve it in both side

first i use LHS

then i solve RHS

then i get same answer
hope u got it