Question

1+sin2A-cos2A/1+sin2A+cos2A=tanA

Answer 1

whenever u have to prove this types of identity first apply formulas to elaborate the terms and do maximum conversion to nullify the opposite sign terms.

Answer 2

1) (1 + SIN2A - COS2A)/(1+SIN2A + COS2A) = TANA

SIN2A =2TANA/1+TAN2A & COS2A =1-TAN2A/1+TAN2A
PUTTING THESE
LHS =(2TAN2A + 2TANA)/2TANA+2
=TANA = RHS

HENCE PROVED

this is your answer..