1 +sin2a+cos2a/sin a +cos 3a =2 cos a
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LHS
=1+cos2A+sin2A
-------------------------
sinA+cosA
=(2cos²A+2sinA cosA)
------------------------------------
sinA+cosA
=2cosA(sinA + cos A)
------------------------------------
(sinA+cosA)
=2cosA= RHS....
Proved...
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