Math, asked by amulyaattalur41, 2 months ago

1 +sin2a+cos2a/sin a +cos 3a =2 cos a​

Answers

Answered by ynsteja
0

LHS

=1+cos2A+sin2A

-------------------------

sinA+cosA

=(2cos²A+2sinA cosA)

------------------------------------

sinA+cosA

=2cosA(sinA + cos A)

------------------------------------

(sinA+cosA)

=2cosA= RHS....

Proved...

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