(1 – sin²o
- Simplify 11- 20
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1 - sin^2 x = cos^2 x and 1 - cos^2 x = sin^2 x
Therefore,
square root of (1 - sin^2 x / - cos^2 x) = square root of (cos^2 x / sin^2 x) = square root of (cot^2 x) = cot x
Therefore,
square root of (1 - sin^2 x / - cos^2 x) = square root of (cos^2 x / sin^2 x) = square root of (cot^2 x) = cot x
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your answer is one upon cos square theta.
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