Question

1+sin2theta /1-sin2theta =tansqure (π/4+theta​

Answer 1

Answer:

Step-by-step explanation:

ive denoted theta by @

LHS=>1+2tan@/1+tan²@/1-2tan@/1+tan²@

=>1+tan²@+2tan@/1+tan²@-2tan@

now we will simplify RHS

RHS=>tan²(pi/4+@)

=>(tan(pi/4)+tan@/1-tan(pie/4)×tan@)²

As we know tan(pi/4)=1

then,

RHS=>(1+tan@/1-tan@)²

using (a+b)²and (a-b)² identities

we get->

RHS=> 1+tan²@+2tan@/1+tan²@-2tan@

LHS=RHS

hence proved