Question

1+sin2x=1/4,then sinx+cosx=?​

Answer 1

Answer:

=> ± ½

Step-by-step explanation:

We know,

=> sin2x = 2 sinx cosx

=> 1 = sin²x + cos²x

Now,

=> 1 + sin2x = ¼

=> sin²x + cos²x + 2sinxcosx = ¼

=> (sin x)² + (cos x)² + 2 sinx cosx = ¼

=> (sin x + cos x)² = ¼

=> sin x + cos x = √¼ =± ½