1+sin2x=1/4,then sinx+cosx=?
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Answer:
=> ± ½
Step-by-step explanation:
We know,
=> sin2x = 2 sinx cosx
=> 1 = sin²x + cos²x
Now,
=> 1 + sin2x = ¼
=> sin²x + cos²x + 2sinxcosx = ¼
=> (sin x)² + (cos x)² + 2 sinx cosx = ¼
=> (sin x + cos x)² = ¼
=> sin x + cos x = √¼ =± ½
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