√(1+sin2x)=√(sin²x+cos²x+2sinx.cosx)
How this is possible ??
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Answered by
0
Answer:
I don't know but
Step-by-step explanation:
but I am try this question because is interesting
Answered by
0
Step-by-step explanation:
√1+sin2x= √(cosx+sinx)^2=sinx+cosx
√sin^2 x+cos^2 x+2sinxcosx
=√1+sin2x
=sinx+cosx (proved)
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