Question

1-sin60° ÷ cos 60° = tan60°-1÷tan60°+1
show that ​

Answer 1

Answer:

Sin 60°/cos 60°

=(1-√3/2)/(1/2)

=(2-√3)/2×2/1

2-√3

tan 60°-1/tan 60°+1

=(√3-1)/(√3+1)

(√3-1)(√3-1)/(√3+1)(√3-1)

=(3-2√3+1)/(3-1/

=(4-2√3)/2

2(2-√)/2

2(2-√3)/2

=2-√3

LHS=RHS